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x=-15x^2+300x+12.000
We move all terms to the left:
x-(-15x^2+300x+12.000)=0
We get rid of parentheses
15x^2-300x+x-12.000=0
We add all the numbers together, and all the variables
15x^2-299x-12=0
a = 15; b = -299; c = -12;
Δ = b2-4ac
Δ = -2992-4·15·(-12)
Δ = 90121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-299)-\sqrt{90121}}{2*15}=\frac{299-\sqrt{90121}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-299)+\sqrt{90121}}{2*15}=\frac{299+\sqrt{90121}}{30} $
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